Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 51: 51


Equation: $3(x-4)=3(2-2x)$ Solution set : $\{ 2 \}$

Work Step by Step

In the $\fbox{$Y=$}$ screen, read the functions that have been entered: $y_{1}=3(x-4)$ and $y_{2}=3(2-2x).$ The equation to solve is to find x for which $y_{1}= y_{2}$, that is $3(x-4)=3(2-2x)$ In the table of function values screen, we find that when$\quad x=2 \qquad $(row 6) then$\quad y_{1}=y_{2}=-6$ meaning that $x=2$ is the solution to the equation. Equation: $3(x-4)=3(2-2x)$ Solution set : $\{ 2 \}$
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