Intermediate Algebra for College Students (7th Edition)

if $x=−2, y=\frac{1}{2}$ --> $(−2,\frac{1}{2})$ if $x=−1, y=−\frac{1}{-1}$ --> $(−1,1)$ if $x=−\frac{1}{2}$, $y=2$ --> $(−\frac{1}{2},2)$ if $x=−\frac{1}{3}$, $y=3$ --> $(−\frac{1}{3},3)$ if $x=\frac{1}{3}$, $y=-3$ --> $(\frac{1}{3},-3)$ if $x=\frac{1}{2}$, $y=-2$ --> $(\frac{1}{2},-2)$ if $x=1$, $y=-1$ --> $(1,-1)$ if $x=2$, $y=-\frac{1}{2}$ --> $(2,-\frac{1}{2})$
$$y=-\frac{1}{x}$$ (Let $x=−2,−1,−\frac{1}{2},−\frac{1}{3},\frac{1}{3},\frac{1}{2},1,$ and $2$.) Substitute the values of x to the equation: if $x=−2, y=\frac{1}{2}$ --> $(−2,\frac{1}{2})$ if $x=−1, y=−\frac{1}{-1}$ --> $(−1,1)$ if $x=−\frac{1}{2}$, $y=2$ --> $(−\frac{1}{2},2)$ if $x=−\frac{1}{3}$, $y=3$ --> $(−\frac{1}{3},3)$ if $x=\frac{1}{3}$, $y=-3$ --> $(\frac{1}{3},-3)$ if $x=\frac{1}{2}$, $y=-2$ --> $(\frac{1}{2},-2)$ if $x=1$, $y=-1$ --> $(1,-1)$ if $x=2$, $y=-\frac{1}{2}$ --> $(2,-\frac{1}{2})$