## Intermediate Algebra for College Students (7th Edition)

$y_{1}=x^{2}$ $y_{2}=2-x$ For, $y_{1}=y_{2},$ $x^{2}=2-x.$ $x^{2}+x-2=0$ $x^{2}+2x-x-2=0$ $x(x+2)-(x+2)=0$ $(x-1)(x+2)=0$ So, $x=1,-2.$