#### Answer

The values of x are 1 and -2.

#### Work Step by Step

$y_{1}=x^{2}$
$y_{2}=2-x$
For, $y_{1}=y_{2}, $
$x^{2}=2-x.$
$x^{2}+x-2=0$
$x^{2}+2x-x-2=0$
$x(x+2)-(x+2)=0$
$(x-1)(x+2)=0$
So, $x=1,-2.$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

The values of x are 1 and -2.

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