Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.3 - Graphing Equations - Exercise Set - Page 37: 42

Answer

The graph of the equation $y=x^{2}+2$ is a parabola that opens upward with points $(0,2), (1,3), (-1,3), (2,6),$ and $(-2,6)$.
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Work Step by Step

$$y=x^{2}+2$$ The best way to graph this equation is to set values of $x$, then get the corresponding value of $y$ using the equation. Thus, if $x=0$, $y=x^{2}+2$ $y=0^{2}+2$ $y=2$ if $x=1$ $y=1^{2}+2$ $y=1+2$ $y=3$ if $x=-1$ $y=-1^{2}+2$ $y=1+2$ $y=3$ if $x=2$ $y=2^{2}+2$ $y=4+2$ $y=6$ if $x=-2$ $y=-2^{2}+2$ $y=4+2$ $y=6$ Thus, you have points $(0,2), (1,3), (-1,3), (2,6),$ and $(-2,6)$.
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