## Intermediate Algebra for College Students (7th Edition)

The points are $(1,1)$ and $(-2,4)$.
$y_{1}=x^{2},$ $y_{2}=2-x,$ Therefore, when they intersect, the y values have to be equal. i.e. $y_{1}=y_{2},$ So, $x^{2}=2-x,$ $x^{2}+x-2=0,$ $x^{2}+2x-x-2=0,$ $x(x+2)-(x+2)=0,$ $(x-1)(x+2)=0,$ So, $x=1,-2.$ For $x=1,y=1$ For $x=-2,y=4$ So, the points are $(1,1)$ and $(-2,4)$