Answer
The graph is a parabola facing down, with points $(0,3)$, $(\sqrt 3, 0)$ and $(-\sqrt 3,0)$.
Work Step by Step
$$y=3-x^{2}$$
To get the intercepts, set x to zero:
$$y=3-x^{2}$$ $$y=3-0^{2}$$ $$y=3$$
Hence, you get the point (0,3).
Next, set y to zero:
$$y=3-x^{2}$$ $$0=3-x^{2}$$ $$3=x^{2}$$ $$x=±\sqrt 3$$
Hence, the points $(\sqrt 3, 0)$ and $(-\sqrt 3,0)$.
