Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set - Page 12: 26

Answer

44

Work Step by Step

First, we must substitute x and y into the expression $(8)^{2}-4(8-3)$ To solve, we follow order of operations: parenthesis: $(8)^{2}-4(5)$ exponents: $64-4(5)$ multiplication: $64-20$ subtraction: $=44$
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