## Intermediate Algebra for College Students (7th Edition)

Substitute x=9 into the expression: $4+5(9-7)^{3}$ We follow order of operations: First we solve what's in the parenthesis: $4+5(2)^{3}$ Then, exponents: $4+5(8)$ Then, multiply outside the parenthesis: $4+40$ Finally, add: $44$