#### Answer

$1\frac{1}{9}$

#### Work Step by Step

Substitute x into the expression: $(\frac{1}{3})^{2}+3(\frac{1}{3})$
Then, we solve by following order of operations, first multiplying and then adding:
$(\frac{1}{3})(\frac{1}{3})+\frac{3}{3}$
= $\frac{1}{9}+\frac{3}{3}$
=$\frac{1}{9}+1$
= $1\frac{1}{9}$