## Intermediate Algebra for College Students (7th Edition)

$1\frac{1}{9}$
Substitute x into the expression: $(\frac{1}{3})^{2}+3(\frac{1}{3})$ Then, we solve by following order of operations, first multiplying and then adding: $(\frac{1}{3})(\frac{1}{3})+\frac{3}{3}$ = $\frac{1}{9}+\frac{3}{3}$ =$\frac{1}{9}+1$ = $1\frac{1}{9}$