Intermediate Algebra for College Students (7th Edition)

$46$
First, we must substitute x and y into the expression: $(8)^{2}-3(8-2)$ We now follow order of operations: First, we work inside the parenthesis $(8)^{2}-3(6)$ Then, we consider exponents $64-3(6)$ Then, we multiply outside of the parenthesis $64-18$ Finally, we subtract: $46$