Intermediate Algebra for College Students (7th Edition)

First, we substitute the value of x into the expression: $6+5(8-6)^{3}$ We now follow order of operations: First, we solve inside the parenthesis: $6+5(2)^{3}$ Then, we consider exponents (powers): $6+5(8)$ Then, we multiply: $6+40$ Finally, we add: 46