Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 669: 5

Answer

Domain: $x\geq 0$ Range: $y\geq 0$

Work Step by Step

Given \begin{equation} h(x)=5 \sqrt{x}. \end{equation} The radicand of a radical function must be positive. This means that we must have $x\geq 0$. Also, we see that the function's value must satisfy $y\geq 0$ because $$\sqrt x\geq 0\implies 5\sqrt x\geq 0\implies y\geq 0.$$ We got: \begin{equation} \begin{aligned} \textbf{Domain :}\quad & x\geq 0\\ \textbf{Range :}\quad & y\geq 0\\\\ \end{aligned} \end{equation}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.