Answer
1) Domain: $x\geq 6$
Work Step by Step
Given \begin{equation}
f(x)=\sqrt{x-6}.
\end{equation} This is an even root function because the index, $n=2$, is even. The radicand must be positive. So, we require $x-6 \geq 0 \Longrightarrow x \geq 6$.
1)The domain is $x\geq 6$.
Make a table of the function, $f(x)$ versus $x$.
\begin{equation}
\begin{array}{|c|cccc|}
\hline \boldsymbol{x} & 10& 15 & 20 & 30 \\
\hline \boldsymbol{f}(\boldsymbol{x})=\sqrt{\boldsymbol{x}-\mathbf{6}} & 2.0 & 3.0 & 3.7 & 4.9 \\
\hline
\end{array}
\end{equation} 2) See the graph.
