Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 581: 44

Answer

$= \frac{2t}{(t+2)}$

Work Step by Step

$\frac{t^{2}+8t+15}{t^{2}-9} \times \frac{2t^{2}-6t}{t^{2}+7t+10}$ $= \frac{(t+3)(t+5)}{(t-3)(t+3)} \times \frac{2t(t-3)}{(t+5)(t+2)}$ $= \frac{(t+3)(t+5)}{(t+3)} \times \frac{2t}{(t+5)(t+2)}$ $= \frac{(t+5)}{1} \times \frac{2t}{(t+5)(t+2)}$ $= \frac{2t(t+5)}{(t+5)(t+2)}$ $= \frac{2t}{(t+2)}$
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