Answer
$= \log (16a^{17}b^{15})$
Work Step by Step
$= 4\log (2a^{3}) + 5 \log (ab^{3})$
$= \log (2a^{3})^{4} + \log (ab^{3})^{5}$
$= \log (16a^{12}) + \log (a^{5}b^{15})$
$= \log (16a^{12})(a^{5}b^{15})$
$= \log (16a^{17}b^{15})$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 8
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