Answer
$g^{-1}(x) = 15^{x}$
Work Step by Step
$g(x) = \log_{15} x$
Let $g(x) = y$
$y = \log_{15} x$
Swap the variables $x$ and $y$ and then solve for $y$ to find the inverse:
$x = \log_{15} y$
$y = 15^{x}$
$g^{-1}(x) = 15^{x}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 16
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