Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 16


$g^{-1}(x) = 15^{x}$

Work Step by Step

$g(x) = \log_{15} x$ Let $g(x) = y$ $y = \log_{15} x$ Swap the variables $x$ and $y$ and then solve for $y$ to find the inverse: $x = \log_{15} y$ $y = 15^{x}$ $g^{-1}(x) = 15^{x}$
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