Answer
$x = - \frac{3}{8}$
Work Step by Step
$\log_{16} (2x+1) = -0.5$
$\log_{16} (2x+1) = -\frac{1}{2}$
$16^{-\frac{1}{2}} = 2x+1$
$2x + 1 = \frac{1}{4}$
$8x + 4 = 1$
$8x = 1 - 4$
$8x = -3$
$x = - \frac{3}{8}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 3
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