Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Test: 3

Answer

$x = - \frac{3}{8}$

Work Step by Step

$\log_{16} (2x+1) = -0.5$ $\log_{16} (2x+1) = -\frac{1}{2}$ $16^{-\frac{1}{2}} = 2x+1$ $2x + 1 = \frac{1}{4}$ $8x + 4 = 1$ $8x = 1 - 4$ $8x = -3$ $x = - \frac{3}{8}$
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