Answer
$= 2.63 \times 10^{-3} M$
Work Step by Step
$pH = -\log [H^{+}]$
$2.58 = -\log [H^{+}]$
$2.58 = -\log_{10} [H^{+}]$
$[H^{+}] = 10^{-2.58}$
$= 0.002630 M$
$= 2.63 \times 10^{-3} M$
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