Answer
$x = \frac{\frac{\log 8}{\log 3} + 1}{7}$
Work Step by Step
$8 = 3^{7x-1}$
$\log 8 = \log 3^{7x-1}$
$\log 8 = (7x-1)\log 3$
$\frac{\log 8}{\log 3} = 7x-1$
$7x = \frac{\log 8}{\log 3} + 1$
$x = \frac{\frac{\log 8}{\log 3} + 1}{7}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 6
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