Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 51: 19



Work Step by Step

To find 3 points to plot for the equation $x=−1.5y+7$, first, rewrite the equation in slope-intercept form: $y=mx+b$. Isolate $y$ by subtracting 7 from each side of the equation to get $x-7=−1.5y$ Now, divide -1.5 on each side of the equation to get -$\frac{2}{3}$$x$+$\frac{14}{3}$$=y$ This reads the same as $y=$-$\frac{2}{3}$$x$+$\frac{14}{3}$ Now, substitute 3 values of x into the equation to get three values of y. For this example, I used -1,0, and 1. $y=$-$\frac{2}{3}$$(-1)$+$\frac{14}{3}$$=$$\frac{16}{3}$$=$$5$$\frac{1}{3}$ $y=$-$\frac{2}{3}$$(0)$+$\frac{14}{3}$$=$$\frac{14}{3}$$=$$4$$\frac{2}{3}$ $y=$-$\frac{2}{3}$$(1)$+$\frac{14}{3}$$=$$\frac{12}{3}$$=4$ Display these x and y values in a table and then graph.
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