Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises: 15



Work Step by Step

The equation to graph by plotting 3 points is $x=\frac{2}{3}$$y$$-4$. However, it will be easier to solve if we write this equation in slope-intercept form: To get $y$ by itself, add 4 to both sides of the equation to get $x+4=\frac{2}{3}y$ Now, divide $\frac{2}{3}$ on each side of the equation to get $\frac{3}{2}x$$+6$=$y$ Rewrite with $y$ in front as $y=$$\frac{3}{2}x$$+6$ This explanation will plug in -2,0, and 2 for x, but any 3 numbers can be used: $y=$$\frac{3}{2}(-2)$$+6=3$ $y=$$\frac{3}{2}(0)$$+6=6$ $y=$$\frac{3}{2}(2)$$+6=9$ These three solutions provide an x and y-coordinate for each point. The numbers substituted for x will be the x-coordinates and the solutions to that will be the y-coordinates: (−2,3), (0,6), and (2,9).
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