Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 51: 16



Work Step by Step

The equation to graph by plotting 3 points is $x=\frac{3}{4}y+1$. However, it will be easier to solve if we write this equation in slope-intercept form: To get y by itself, subtract 1 to both sides of the equation to get $x-1=$$\frac{3}{4}y$ Now, divide $\frac{3}{4}$ on each side of the equation to get $\frac{4}{3}x$$-$$\frac{4}{3}$$=y$ Rewrite with y in front as $y=$$\frac{4}{3}x$$-$$\frac{4}{3}$ This explanation will plug in -4,0, and 4 for x, but any 3 numbers can be used: $\frac{4}{3}(-4)$$-$$\frac{4}{3}$$=-6\frac{2}{3}$ $\frac{4}{3}(0)$$-$$\frac{4}{3}$$=$-$\frac{4}{3}$ $\frac{4}{3}(4)$$-$$\frac{4}{3}$$=4$ These three solutions provide an x and y-coordinate for each point. The numbers substituted for x will be the x-coordinates and the solutions to that will be the y-coordinates: $(−4,-6\frac{2}{3})$, $(0,$-$\frac{4}{3})$, and $(4,4)$.
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