Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises - Page 51: 13

Answer

Graph:
1521950385

Work Step by Step

The equation to graph by plotting 3 points is $y=\frac{2}{3}$$x$$+6$. This explanation will plug in -3,0, and 3 for $x$, but any 3 numbers can be used: $y=\frac{2}{3}$$(-3)$$+6=4$ $y=\frac{2}{3}$$(0)$$+6=6$ $y=\frac{2}{3}$$(3)$$+6=8$ These three solutions provide an x and y-coordinate for each point. The numbers substituted for x will be the x-coordinates and the solutions to that will be the y-coordinates: $(-3,4)$, $(0,6)$, and $(3,8)$.
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