Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.3 Fundamentals of Graphing and Slope - 1.3 Exercises: 11

Answer

Graph:
1521691938

Work Step by Step

The equation $y=x^{2}+2$ will actually create a parabola because of $x$ being to a power of, in this case, 2. Plug and chug to find five points on the graph. Let's use -2,-1,0,1 and 2 as the five x-coordinates in order to keep the points symmetrical to one another. However, you can use any five values of x. $y=(-2)^{2}+2$=$6$ $y=(-1)^{2}+2$=$3$ $y=(0)^{2}+2$=$2$ $y=(1)^{2}+2$=$3$ $y=(2)^{2}+2$=$6$ The five coordinates to graph are $(-2,6)$,$(-1,3)$,$(0,2)$,$(1,3)$,$(2,6)$.
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