Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 681: 104

Answer

$\frac{20}{97}+\frac{45}{97}i$

Work Step by Step

Given \begin{equation} \frac{5}{4-9 i}. \end{equation} Rationalize the denominator and simplify. \begin{equation} \begin{aligned} \frac{5}{4-9 i}&=\frac{5}{4-9 i}\cdot \frac{(4+9i)}{(4+9i)}\\ &= \frac{5(4+9i)}{4^2+9^2}\\ &= \frac{20+45i}{97}\\ &= \frac{20}{97}+\frac{45}{97}i. \end{aligned} \end{equation} Hence \begin{equation} \frac{5}{4-9 i}=\frac{20}{97}+\frac{45}{97}i. \end{equation}
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