Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 681: 100

Answer

$40$

Work Step by Step

Step 1: $(2+6i)(2-6i)$ Step 2: $2(2-6i)+6i(2-6i)$ Step 3: $4-12i+12i-36i^{2}$ Step 4: $4-36i^{2}$ Step 5; As $i^{2}=-1$, $4-36i^{2}=4+36=40$
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