## Intermediate Algebra: Connecting Concepts through Application

$50-10i$
Step 1: $(2-6i)(4+7i)$ Step 2: $2(4+7i)-6i(4+7i)$ Step 3: $8+14i-24i-42i^{2}$ Step 4: As $i^{2}=-1$, we get $8+14i-24i-42(-1)$. Step 5: $8+42+14i-24i$ Step 6: $50-10i$