Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 681: 101

Answer

$50-10i$

Work Step by Step

Step 1: $(2-6i)(4+7i)$ Step 2: $2(4+7i)-6i(4+7i)$ Step 3: $8+14i-24i-42i^{2}$ Step 4: As $i^{2}=-1$, we get $8+14i-24i-42(-1)$. Step 5: $8+42+14i-24i$ Step 6: $50-10i$
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