Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 9a



Work Step by Step

Substituting $x=100$ in the equation $C(x)=\dfrac{2.6x+10,000}{x}$, then, \begin{array}{l} C(100)=\dfrac{2.6(100)+10,000}{100} \\\\ C(100)=\dfrac{260+10,000}{100} \\\\ C(100)=\dfrac{10,260}{100} \\\\ C(100)=102.60 .\end{array} Hence, the cost is $ 102.60 $.
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