Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 4

Answer

$f(x)= 1/3*x+20/3$

Work Step by Step

Through the point $(-2,6)$ and perpendicular to $f(x)=-3x+4$ Perpendicular lines have slopes whose product is -1 $-3*x=-1$ $-3*x/-3=-1/-3$ $x=1/3$ $y=mx+b$ $6=1/3*-2+b$ $6=-2/3+b$ $6+2/3=-2/3+b+2/3$ $20/3=b$ $y=1/3*x+20/3$ $f(x)= 1/3*x+20/3$
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