Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 11a

Answer

$\dfrac{3x}{2}$

Work Step by Step

Adding the numerators, copying the denominator, and then cancelling the common factor between the numerator and the denominator result to \begin{array}{l} \dfrac{x}{4}+\dfrac{5x}{4} \\\\= \dfrac{6x}{4} \\\\= \dfrac{2\cdot3x}{2\cdot2} \\\\= \dfrac{3x}{2} .\end{array}
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