Answer
$\dfrac{6y^{2}}{7}$
Work Step by Step
Using $\dfrac{a^m}{a^n}=a^{m-n}$, then,
\begin{array}{l}
\dfrac{12y^{10}z^{7}}{14y^8z^7}
\\\\
\dfrac{6y^{10-8}z^{7-7}}{7}
\\\\
\dfrac{6y^{2}z^{0}}{7}
\\\\
\dfrac{6y^{2}}{7}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Cumulative Review - Page 600: 7d
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