Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 16



Work Step by Step

The expression $ \dfrac{x^3-8}{x-2} $ simplifies to \begin{array}{l} \dfrac{(x-2)(x^2+2x+4)}{x-2} &\text{... use $a^3-b^3=(a-b)(a^2+ab+b^2)$} \\\\ x^2+2x+4 &\text{... cancel $(x-2)$} .\end{array}
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