Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 510: 31

Answer

$(-∞,-4)$ U $(4,6)$

Work Step by Step

$(2x-8)(x+4)(x-6) \leq 0$ $2x-8\leq 0$ $2x-8+8 \leq 0$ $2x \leq 8$ $2x/2 \leq 8/2$ $x \leq 4$ $x+4 \leq 0$ $x+4-4 \leq 0-4$ $x \leq -4$ $x-6\leq 0$ $x-6+6 \leq 0+6$ $x \leq 6$ We have four sections: $(-∞,-4)$, $(-4, 4)$, $(4,6)$, and $(6, ∞)$. We need to test one value for $x$ in each section to determine if the section would be a solution set. Since we have the $\leq$ sign, we exclude the end points and use parentheses instead of brackets. Let $x=-5$, $x=0$, $x=5$, and $x=10$ $x=-5$ $(2x-8)(x+4)(x-6) \leq 0$ $(2*-5-8)(-5+4)(-5-6) \leq 0$ $(-10-8)(-1)(-11) \leq 0$ $-18*11 \leq 0$ $-198 \leq 0$ (true) $x=0$ $(2x-8)(x+4)(x-6) \leq 0$ $(2*0-8)(0+4)(0-6) \leq 0$ $(0-8)*4*-6 \leq 0$ $-8 *-24 \leq 0$ $192 \leq 0$ (false) $x=5$ $(2x-8)(x+4)(x-6) \leq 0$ $(2*5-8)(5+4)(5-6) \leq 0$ $(10-8)(9)(-1)\leq 0$ $2*-9 \leq 0$ $-18 \leq 0$ (true) $x=10$ $(2x-8)(x+4)(x-6) \leq 0$ $(2*10-8)(10+4)(10-6) \leq 0$ $(20-8)(14*4)\leq 0$ $12 *56 \leq 0$ $672 \leq 0$ (false)
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