Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 510: 28

Answer

$(-∞,-7/6)$ U $(12/7, ∞)$

Work Step by Step

$(6x+7)(7x-12)>0$ $6x+7>0$ $6x+7-7 >0-7$ $6x>-7$ $6x/6>-7/6$ $x > -7/6$ $7x-12>0$ $7x-12+12>0+12$ $7x>12$ $7x/7 > 12/7$ $x > 12/7$ We have three sections: $(-∞,-7/6)$, $(-7/6, 12/7)$, and $(12/7, ∞)$. We need to test one value for $x$ in each section to determine if the section would be a solution set. Since we have the > sign, we exclude the end points and use parentheses instead of brackets. Let $x=-2$, $x=0$, and $x=3$ $x=-2$ $(6x+7)(7x-12)>0$ $(6*-2+7)(7*-2-12)>0$ $(-12+7)(-14-12)>0$ $-5*-26>0$ $130 >0$ (true) $x=0$ $(6x+7)(7x-12)>0$ $(6*0+7)(7*0-12)>0$ $(0+7)(0-12)>0$ $7*-12>0$ $-84>0$ (false) $x=3$ $(6x+7)(7x-12)>0$ $(6*3+7)(7*3-12)>0$ $(18+7)(21-12)>0$ $25*9>0$ $225 >0$ (true)
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