Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 66

Answer

$x=\pm\dfrac{8\sqrt{7}}{7}$

Work Step by Step

Multiplying both sides by the $LCD= 8x^2 ,$ the solution/s to the given equation, $ \dfrac{7}{8}=\dfrac{8}{x^2} ,$ is/are \begin{array}{l}\require{cancel} x^2(7)=8(8) \\\\ 7x^2=64 \\\\ x^2=\dfrac{64}{7} \\\\ x=\pm\sqrt{\dfrac{64}{7}} \\\\ x=\pm\dfrac{\sqrt{64}}{\sqrt{7}} \\\\ x=\pm\dfrac{8}{\sqrt{7}} \\\\ x=\pm\dfrac{8}{\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}} \\\\ x=\pm\dfrac{8\sqrt{7}}{(\sqrt{7})^2} \\\\ x=\pm\dfrac{8\sqrt{7}}{7} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.