Answer
The vertex is labeled with its coordinates, and the green line is the axis of symmetry.
Work Step by Step
$G(x)=(x+5)^2$
$G(x)=(x+5)(x+5)$
$G(x)=x^2+10x+25$
$a=1$, $b=10$, $c=25$
The axis of symmetry is at $x=-b/2a$
$x=-b/2a$
$x=-10/2*1$
$x=-10/2$
$x=-5$
The vertex is at $x=-5$
$G(x)=(x+5)^2$
$G(-5)=(-5+5)^2$
$G(-5)=0^2$
$G(-5)=0$
$(-5, 0)$ is the vertex.
