Answer
The vertex is labeled with its coordinates, and the green line is the axis of symmetry.
Work Step by Step
$F(x)=(x-1)^2$
$F(x)=(x-1)(x-1)$
$F(x)=x^2-2x+1$
$a=1$, $b=-2$, $c=1$
The axis of symmetry is at $x=-b/2a$
$x=-b/2a$
$x=-(-2)/2*1$
$x=2/2$
$x=1$
The vertex is at $x=1$
$F(x)=(x-1)^2$
$F(1)=(1-1)^2$
$F(1)=0^2$
$F(1)=0$
$(1, 0)$ is the vertex.
