Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 59

Answer

$y=\pm2$

Work Step by Step

Step 1: $9y^{2}=36$ Step 2: $y^{2}=\frac{36}{9}$ Step 3: $y^{2}=4$ Step 4: $y=\pm\sqrt 4$ Step 5: $y=\pm2$
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