Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 63

Answer

$x=\pm i\sqrt {11}$

Work Step by Step

$x^{2}+11=0$ $x^{2}=-11$ $x=\pm\sqrt {-11}$ $x=\pm\sqrt {-1\times11}$ $x=\pm\sqrt {-1}\times\sqrt {11}$ $x=\pm i\times\sqrt {11}$ $x=\pm i\sqrt {11}$
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