Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Review - Page 532: 54b

Answer

The line of symmetry is at $x=3.75$. This means that the graph is reflexive over this line. For any point on the right hand side of the graph with a given $y$ value, there is another point $x$ that has the same $y$ value. Example: For $x=.4$ and $x=7.1$, both points have a y-value of 350. That is why part (a) has two answers.

Work Step by Step

$h(t) =-16t^2+120t+300$ $x=-16$, $b=120$, $c=300$ $x=-b/2a$ $x=-120/2*-16$ $x=-120/-32$ $x=60/16$ $x=30/8$ $x=15/4$ $x=3.75$ Line of symmetry is at $x=3.75$ $h(t)=350$ $350=-16t^2+120t+300$ $350-350=-16t^2+120t+300-350$ $0=-16t^2+120t-50$ $0=(-16t^2+120t-50)/2$ $0=-8t^2+60t-25$ $a=-8$, $b=60$, $c=-25$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-60±\sqrt {60^2-4*(-8)*-25})/2*-8$ $x=(-60±\sqrt {3600-800})/-16$ $x=(-60±\sqrt {2800})/-16$ $x=(-60±\sqrt {4*7*100})/-16$ $x=(-60±20\sqrt 7)/-16$ $x=(-60±20*2.645)/-16$ $x=(-60±52.915)/-16$ $x=(-60+52.915)/-16$ $x=-7.085/-16$ $x=.4428$ $x=.4$ $x=(-60-52.915)/-16$ $x=-112.915/-16$ $x=7.05625$ $x=7.1$
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