Answer
$-\sqrt[3]{2x}$
Work Step by Step
Using the properties of radicals, then,
\begin{array}{l}
\sqrt[3]{16x}-\sqrt[3]{54x}
\\=
\sqrt[3]{8\cdot2x}-\sqrt[3]{27\cdot2x}
\\=
2\sqrt[3]{2x}-3\sqrt[3]{2x}
\\=
-\sqrt[3]{2x}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 7
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