Answer
$-3y+7$
Work Step by Step
Using the properties of radicals, then,
\begin{array}{l}
2+3\sqrt{y^2}-6\sqrt{y^2}+5
\\=
2+3\cdot y-6\cdot y+5
\\=
2+3y-6y+5
\\=
-3y+7
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 19
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