Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 3

Answer

$10x\sqrt{2x}$

Work Step by Step

Using the properties of radicals, then, \begin{array}{l} 2\sqrt{2x^3}+4x\sqrt{8x} \\= 2\sqrt{x^2\cdot2x}+4x\sqrt{4\cdot2x} \\= 2\cdot x\sqrt{2x}+4x\cdot2\sqrt{2x} \\= 2x\sqrt{2x}+8x\sqrt{2x} \\= 10x\sqrt{2x} .\end{array}
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