Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 438: 22

Answer

$-6\sqrt3$

Work Step by Step

$-\sqrt{75} + \sqrt{12} - 3\sqrt{3}$ $=-\sqrt{3\times25}+\sqrt{3\times4}-3\sqrt{3}$ $=-5\sqrt{3}+2\sqrt{3}-3\sqrt{3}$ $=-6\sqrt{3}$
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