Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 84

Answer

$2x^2+\dfrac{1}{2}x-5$

Work Step by Step

Using the long division below, then \begin{array}{l}\require{cancel}\left( 2x^3+\dfrac{9}{2}x^2-4x-10 \right)\div( x+2 )\\\\= 2x^2+\dfrac{1}{2}x-5 .\end{array}
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