Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 62

Answer

$x=-1$

Work Step by Step

Subtract $1$ to both sides of the equation to have: $\frac{2x}{9}=\frac{7}{9}-1 \\\frac{2x}{9}=\frac{7}{9}-\frac{9}{9} \\\frac{2x}{9}=\frac{-2}{9}$ Multiply 9 to both sides of the equation to have: $9(\frac{2x}{9})=9(\frac{-2}{9}) \\2x=-2 \\x=\frac{-2}{2} \\x=-1$
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