Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 69

Answer

$x^3-9x=x(x-3)(x+3)$

Work Step by Step

Factor out the GCF $x$ to have: $=x(x^2-9)$ Factor the difference of two squares to have: $=x(x-3)(x+3)$
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