## Intermediate Algebra (6th Edition)

$(x^3-5x^2+2x-1) \text{ centimeters}$
Using $A=bh$ or the forumula for the area of a parallelogram, then \begin{array}{l}\require{cancel} A=bh \\\\ x^4-23x^2+9x-5=(x+5)h \\\\ \dfrac{x^4-23x^2+9x-5}{x+5}=h .\end{array} Using the long division method, the quotient of the expression above is shown below. Hence, the height is $(x^3-5x^2+2x-1) \text{ centimeters }.$