Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.4 - Dividing Polynomials: Long Division and Synthetic Division - Exercise Set - Page 371: 65

Answer

$125z^3+8=(5z+2)(25z^2-10z+4)$

Work Step by Step

The given expression can be written as: $=(5z)^3+2^3$ RECALL: A sum or difference of two cubes can be factored using the following: (i) $a^3-b^3=(a-b)(a^2+ab+b^2)$ (ii) $a^3+b^3 = (a+b)(a^2-ab+b^2)$ Use formula (2) above with $a=5z$ and $b=2$ to have: $=(5z+2)[(5z)^2-5z(2)+2^2] \\=(5z+2)(25z^2-10z+4)$
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