## Intermediate Algebra (6th Edition)

The slope is $-\frac{7}{2}$ and the y-intercept is (0,5).
We are given that $7x+2y=10$ First, subtract 7x from both sides. $2y=-7x+10$ Divide both sides by 2. $y=\frac{-7x+10}{2}=-\frac{7}{2}x+5$ The equation is now in the form $y=mx+b$, where m is the slope of the line and b is the y-coordinate of the y-intercept. The slope is $-\frac{7}{2}$ and the y-intercept is (0,5) because the y-intercept is the point at which the line crosses the y-axis, which happens at x=0.